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displacement current and properties of electromagnetic wave questions with solutions
Practice Electromagnetic wave for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
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- MCQmediumElectromagnetic wave
Match List I with List II
List-I
A. Gauss’s law of magnetostatics
B. Faraday’s law of electro magnetic induction
C. Ampere’s law
D. Gauss’s law of electrostaticsList-II
I. ∮E·dA = (1/ε₀)∫ρ dV
II. ∫B.dA= 0
III.∫E.dl= -d/dt ∫ B.dl
IV. ∮B.dl= μ₀I
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JEE Mains 2024 30 Jan Evening Shift
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A parallel-plate capacitor is being charged by a conduction current I. Neglect leakage. The displacement current between the capacitor plates is:
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JEE MainsNEETJEE Advanced
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A circular parallel-plate capacitor of plate radius R is being charged by a constant current I. Assuming a uniform electric field between the plates, the magnetic field at a distance r < R from the axis is:
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JEE MainsNEETJEE Advanced
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A plane electromagnetic wave travels along the +x-axis in free space. Which condition is impossible for the wave?
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JEE MainsNEETJEE Advanced
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The magnetic field of a plane electromagnetic wave is
B = B₀ sin[2πνt-(2πx / λ)] ĵ.
The wave propagates in the +x direction through a medium in which the wave speed is νλ. Which expression gives the associated electric field?
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JEE Mains 2026 4 April Evening Shift
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Which Maxwell equation is specifically required for time-varying magnetic conditions and reduces to the electrostatic form in static conditions?
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JEE Mains13 April 2023Shift 1Morning Shift
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Match the List-I with List-II
List-I
A. Radio-wave
B. Micro-wave
C. Infrared-wave
D. X-rayList-II I. is produced by Magnetron valve II. Due to change in the vibrational modes of atoms III. Due to inner shell electrons moving from higher energy level to lower energy level IV. Due to rapid acceleration of electrons
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JEE Mains 202624 January Morning Shift
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Match List-I with List-II.
List-I (Relation)
A. ∮E·dl = -d/dt ∫B·da
B. ∮B·dl = μ₀[I + ε₀ dΦ(E)/dt]
C. ∮E·da = (1/ε₀)∫ρ dv
D. ∮B·dl= μ₀I
List-II (Law)
I. Ampere's circuital law. II. Faraday's laws of electromagnetic induction. III. Ampere-Maxwell law IV. Gauss's law of electrostatics
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JEE Mains 202623 January Morning Shift
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The electric field associated with an electromagnetic wave travelling in vacuum is given by E₀ sin(3y + 4z + ωt) î, where ω is the angular frequency. All quantities are in SI units. The correct statement(s) about this wave is/are: [Given: speed of light in vacuum c = 3 × 10⁸ m s⁻¹.]
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JEE Advanced2026Paper 1
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A circular parallel-plate capacitor of radius 12 cm is charged by a current of 9 A. Assuming uniform electric field, the displacement current through a concentric circular surface of radius 4 cm between the plates is N ampere. Find N.
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