Free physics question bank
Electric Field & Superposition Principle questions with solutions
Practice Electrostatic for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
Showing 1–10 of 109 questions
- MCQmediumElectrostaticOpen question & full solution →
A thin circular ring of radius R carries total charge q uniformly. A point charge Q of the same sign is placed at the centre. Neglect deformation of the ring. The increase ΔT in the tensile force in the ring is:
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- MCQmediumElectrostatic
Two point charges q₁ = 2 μC and q₂ = 1 μC are placed at distances b = 1 cm and a = 2cm from the origin on the y and x axes as shown in figure the electric field vector at point P(a, b) will subtend an angle θ with x-axis given by -

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JEE MainsAdvanced
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If the line charge densities are λ and -λ. as shown in figure. Find the electric field at P.

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JEE MainsAdvanced
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A uniformly charged thin hemispherical shell of radius R occupies x ≥ 0, with its equatorial plane at x = 0. At the point P(x,0,0), 0 < x < R,the electric field is E.What is the electric field at the mirror point Q(-x,0,0)?

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- MCQmediumElectrostatic
A particle of charge ‘–q’ and mass ‘m’ moves in a circle of radius ‘r’ around an infinitely long line charge of linear density ‘+λ’. Then time period will be given as: (Consider k as Coulomb’s constant)
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JEE Mains 2024 30 Jan Evening Shift
Open question & full solution → - MCQmediumElectrostatic
Two point charges q₁ and q₂ lie on a circle of unit radius. The electric field at the centre is E. If r1 is the position vector of the centre with respect to q₁, find r2, the position vector of the centre with respect to q₂.
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JEE MainsAdvanced
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A wheel having mass m has charges +q and -q on diametrically opposite points. It remains in equilibrium on a rough inclined plane in the presence of uniform vertical electric field E =

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JEE MainsAdvanced
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A thin conducting ring of radius r has an electric charge +Q. If a point charge q is placed at the center of the ring, the increment in tension in the ring will be nπ2ϵοr2Qq . Find n.
JEE MainsAdvanced
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Two particles of mass m each, carrying charges +q and -q, are joined by a light rod of length 6a as shown. The system is on a horizontal frictionless surface. Two springs are connected to the rod, which is hinged at C. A uniform electric field exists throughout the region. The rod is given a small angular displacement from equilibrium. If the frequency of small oscillation is ν, find 4ν. Given m =3π2k kg and Eq = 8ka.

JEE MainsAdvanced
Open question & full solution → - NumericmediumElectrostatic
Consider a regular cube with charge +Q at every corner except one corner, where the charge is -Q. The distance from every corner to the centre P is r. If the electric-field magnitude at P is E = nkQ/r², find n.

JEE MainsAdvanced
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