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Instantaneous speed and instantaneous velocity questions with solutions
Practice Kinematics Part-1 (one dimension) for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
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- A/RdifficultKinematics Part-1 (one dimension)Open question & full solution →
Evaluate the following Assertion (A) and Reason (R) and choose the correct option.
Assertion
Assertion (A): For x(t) = 4t³ - 3t, t ≥ 0, the particle initially moves in the negative x-direction, comes momentarily to rest, and then reverses its direction.
Reason
Reason (R): Its velocity is v = dx/dt = 12t² - 3, which changes sign from negative to positive at t = 1/2 s.
Options
- MCQeasyKinematics Part-1 (one dimension)
The position of a particle is r=(5t² î-5t ĵ) m. The magnitude and direction of its velocity at t=1/2 s are:
Options
JEE Mains 2025 24 Jan Evening Shift
Open question & full solution → - IntegerdifficultKinematics Part-1 (one dimension)
The displacement and the increase in the velocity of a moving particle in the time interval t to (t+1)s are 125 m and & 50 m/s respectively. The distance travelled by the particle in (t+2)ths is ________m.
JEE Main 2024 (Online) 30th January Morning Shiftkinematics previous year
Open question & full solution → - MCQeasyKinematics Part-1 (one dimension)
The distance travelled by a particle is related to time t as x = 4t². The velocity of the particle at t = 5s is :
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JEE Mains25 January 2023Shift 2Evening Shift
Open question & full solution → - MCQeasyKinematics Part-1 (one dimension)
The distance travelled by an object in time t is given by s = 2.5t². The instantaneous speed at t = 5 s is:
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13 April 2023 Evening Shift
Open question & full solution → - MCQmediumKinematics Part-1 (one dimension)
The position of a particle is x = (5t² - 4t + 5) m. The magnitude of its velocity at t = 2 s is:
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15 April 2023 Morning Shift
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