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Instantaneous speed and instantaneous velocity questions with solutions

Practice Kinematics Part-1 (one dimension) for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.

Showing 1–6 of 6 questions

  • A/RdifficultKinematics Part-1 (one dimension)

    Evaluate the following Assertion (A) and Reason (R) and choose the correct option.

    Assertion

    Assertion (A): For x(t) = 4t³ - 3t, t ≥ 0, the particle initially moves in the negative x-direction, comes momentarily to rest, and then reverses its direction.

    Reason

    Reason (R): Its velocity is v = dx/dt = 12t² - 3, which changes sign from negative to positive at t = 1/2 s.

    Options

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  • MCQeasyKinematics Part-1 (one dimension)

    The position of a particle is r\vec{r}=(5t² î-5t ĵ) m. The magnitude and direction of its velocity at t=1/2 s are:

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    JEE Mains 2025 24 Jan Evening Shift

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  • IntegerdifficultKinematics Part-1 (one dimension)

    The displacement and the increase in the velocity of a moving particle in the time interval t to (t+1)s are 125 m and & 50 m/s respectively. The distance travelled by the particle in (t+2)th(t+2)^{th}s is ________m.

    JEE Main 2024 (Online) 30th January Morning Shiftkinematics previous year

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  • MCQeasyKinematics Part-1 (one dimension)

    The distance travelled by a particle is related to time t as x = 4t². The velocity of the particle at t = 5s is :

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    JEE Mains25 January 2023Shift 2Evening Shift

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  • MCQeasyKinematics Part-1 (one dimension)

    The distance travelled by an object in time t is given by s = 2.5t². The instantaneous speed at t = 5 s is:

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    13 April 2023 Evening Shift

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  • MCQmediumKinematics Part-1 (one dimension)

    The position of a particle is x = (5t² - 4t + 5) m. The magnitude of its velocity at t = 2 s is:

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    15 April 2023 Morning Shift

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