A particle has x = (t²−1)² metre for 0 ≤ t ≤ 2 s. Its average speed and average velocity are respectively:

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G1 Physics · Accepted Answer

v = 4t(t²−1). The direction changes at t=1 s. Positions: x(0)=1, x(1)=0, x(2)=9. Distance = |0−1| + |9−0| = 10 m. Displacement = 9−1 = 8 m. Total time = 2 s. Average speed = 10/2=5 m s⁻¹. Average velocity = 8/2=4 m s⁻¹.