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Practice Simple Harmonic Motion for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
Showing 1–10 of 36 questions
- MCQmediumSimple Harmonic Motion
A particle executes simple harmonic motion according to x = a sin(50t+π / 3), where x is in centimetres and t is in seconds. Starting from t = 0, let t₁ be the first time at which the particle comes to rest and t₂ be the first time at which its acceleration becomes zero. What are t₁ and t₂, respectively?
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JEE Mains 2026 2 April Evening Shift
Open question & full solution → - NumericmediumSimple Harmonic Motion
The position, velocity and acceleration of a particle executing simple harmonic motion are found to have magnitudes of 4 m, 2 m s⁻¹ and 16 m s⁻² at a certain instant. The amplitude of the motion is √x m where x is _______.
JEE Mains 2024 09 Apr Morning Shift
Open question & full solution → - MCQmediumSimple Harmonic Motion
Match each time-dependent function in List I with the correct description in List II.
List I:
A. sin²(ωt)
B. sin³(2ωt)
C. sin(ωt)+cos(πωt)
D. cos(ωt)+cos(2ωt)List II: I. Periodic with period π /ω, but not simple harmonic motion II. Periodic with period 2π /ω, but not simple harmonic motion III. Periodic with period π /ω and represents simple harmonic motion about its mean position IV. Non-periodic
Choose the correct matching.
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JEE Mains 2026 5 April Evening Shift
Open question & full solution → - NumericmediumSimple Harmonic Motion
Two particles execute SHM according to x₁ = A sinωt and x₂ = A sin(ωt+π/3). If the first positive time at which their positions are equal is T/N, find N.
JEE MainsNEETJEE Advanced
Open question & full solution → - NumericmediumSimple Harmonic Motion
Two particles execute SHM according to x₁ = A sinωt and x₂ = A sin(ωt+π/3). If the first positive time at which their velocities are exactly equal is 5T/N, find N.
JEE MainsNEETJEE Advanced
Open question & full solution → - NumericmediumSimple Harmonic Motion
A simple harmonic oscillator has an amplitude A and time period 6π second. Assuming the oscillation starts from its mean position, the time required by it to travel from x = A to x = (√3/2)A will be π/x s, where x = _______ :
JEE Mains 2024 29 Jan Evening Shift
Open question & full solution → - MCQmediumSimple Harmonic Motion
Two particles P₁ and P₂ perform SHM on the same line according to x₁ = A sinωt and x₂ = A cosωt. What is the maximum possible distance between the two particles during their motion?
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JEE MainsNEETJEE Advanced
Open question & full solution → - NumericeasySimple Harmonic Motion
A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is _______ cm/s.
JEE Mains 2024 06 Apr Morning Shift
Open question & full solution → - NumericmediumSimple Harmonic Motion
Two particles execute SHM along the same line with equal amplitude A and equal frequency. Their maximum separation is exactly A. If their phase difference is N degrees, where 0 < N < 180, find N.
JEE MainsNEETJEE Advanced
Open question & full solution → - MCQmediumSimple Harmonic Motion
In SHM x=A sinωt with time period 2 s and amplitude 1 cm, the ratio distance/displacement magnitude during the first 1.25 s is:
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JEE Mains 2025 24 Jan Morning Shift
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