Two particles execute SHM according to x₁ = A sinωt and x₂ = A sin(ωt+π/3). If the first positive time at which their positions are equal is T/N, find N.

Question

G1 Physics · Accepted Answer

Equal positions require sinωt = sin(ωt+π/3). The first non-zero solution gives ωt = π/3. Therefore, t = (π/3)/(2π/T) = T/6. Hence, N = 6.