A block is placed on a rough wedge of inclination 37° rising towards the right. The wedge accelerates horizontally towards the right with 5 m/s². Take g = 10 m/s², sin37° = 3/5 and cos37° = 4/5. Minimum coefficient of friction required to keep the block stationary relative to wedge is:
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Question

A block is placed on a rough wedge of inclination 37° rising towards the right. The wedge accelerates horizontally towards the right with 5 m/s². Take g = 10 m/s², sin37° = 3/5 and cos37° = 4/5. Minimum coefficient of friction required to keep the block stationary relative to wedge is:

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G1 Physics · Accepted Answer

In wedge frame pseudo force ma acts left. Along plane, gravity down-plane = mg sinθ and pseudo up-plane = ma cosθ. Net tendency down-plane = m(g sinθ - a cosθ) = m(6-4)=2m. Normal reaction N = m(g cosθ + a sinθ)=m(8+3)=11m. Thus μₘᵢₙ = 2/11. Correct value is 2/11.