A smooth wedge of inclination 37° rises towards the right and accelerates horizontally towards the right with a = 10 m/s². A 2 kg block remains in contact with the inclined surface. Take g = 10 m/s², sin37° = 3/5 and cos37° = 4/5. The normal reaction exerted by the wedge on the block is:
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Question

A smooth wedge of inclination 37° rises towards the right and accelerates horizontally towards the right with a = 10 m/s². A 2 kg block remains in contact with the inclined surface. Take g = 10 m/s², sin37° = 3/5 and cos37° = 4/5. The normal reaction exerted by the wedge on the block is:

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G1 Physics · Accepted Answer

In the wedge frame, gravity mg acts downward and pseudo force ma acts left. Both have components pressing the block into the plane. Thus N = m(g cosθ + a sinθ) = 2[10×(4/5)+10×(3/5)] = 2(8+6)=28 N.