For an electric dipole, the electric field and potential at an axial point a distance r from its centre are E₀ and V₀. What are the electric field magnitude and potential at an equatorial point a distance 2r from the centre?
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Question

For an electric dipole, the electric field and potential at an axial point a distance r from its centre are E₀ and V₀. What are the electric field magnitude and potential at an equatorial point a distance 2r from the centre?

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G1 Physics · Accepted Answer

E a x i s = 2 k P / r 3 = E 0 . E_axis=2kP/r³=E₀. E a ​ x i s = 2 k P / r 3 = E 0 ​ . At distance 2r on the equatorial line, E e q = k P / ( 2 r ) 3 = E 0 / 16. E_eq=kP/(2r)³=E₀/16. E e ​ q = k P / ( 2 r ) 3 = E 0 ​ /16. Also V e q = 0. V_eq=0. V e ​ q = 0. Hence (E₀/16,0).