If I= I A I_A I A sinωt + I B I_B I B cosωt, the rms value of current is:

Question

If I= I A I_A I A ​ sinωt + I B I_B I B ​ cosωt, the rms value of current is:

G1 Physics · Accepted Answer

Write I=I₀sin(ωt+θ), where I₀=√( I A 2 + I B 2 ) . I_A²+I_B²). I A 2 ​ + I B 2 ​ ) . For a sinusoidal current, I r m s = I 0 / √ 2. I_rms=I₀/√2. I r ​ m s = I 0 ​ /√2. Therefore I r m s = √ [ ( I A 2 + I B 2 ) / 2 ] . I_rms=√[(I_A²+I_B²)/2]. I r ​ m s = √ [( I A 2 ​ + I B 2 ​ ) /2 ] .

If I= I A I_A I A ​ sinωt + I B I_B I B ​ cosωt, the rms value of current is:

If I= I A I_A I A sinωt + I B I_B I B cosωt, the rms value of current is: