Average Value, RMS Value and Peak Value of Alternating Current questions with solutions

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• MCQeasyAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  The peak voltage of a sinusoidal AC source equals:

  Options

  • Option A

    the voltage supplied instantaneously

  • Option B

    the RMS voltage

  • Option C

    √2 times the RMS voltage

  • Option D

    1/√2 times the RMS voltage

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• MCQmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  A current i = 5 sinωt + 12 cosωt A flows through a resistor. What is the RMS value of the current?

  Options

  • Option A

    13/√2 A

  • Option B

    17/√2 A

  • Option C

    13 A

  • Option D

    √119 A

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• MCQmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  An alternating current is represented by i = 5√2 + 10cos(650πt + π/6) ampere. The RMS value of the current is:

  Options

  • Option A

    50 A

  • Option B

    100 A

  • Option C

    10 A

  • Option D

    5√2 A

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• A/RmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  Read the following assertion and reason and choose the correct option.

  Assertion

  Assertion (A): The average value of a sinusoidal current over one complete cycle is zero.

  Reason

  Reason (R): The RMS value of the same sinusoidal current is non-zero.

  Options

  • Option A

    Both A and R are true and R is the correct explanation of A.

  • Option B

    Both A and R are true but R is NOT the correct explanation of A.

  • Option C

    A is true but R is false.

  • Option D

    A is false but R is true.

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• MCQmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  During each period T, a current remains +6 A for a time T/3 and -3 A for the remaining 2T/3. Find its average value and RMS value.

  Options

  • Option A

    0 A and 3√2 A

  • Option B

    0 A and 3√3 A

  • Option C

    2 A and 3√2 A

  • Option D

    0 A and 6 A

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• MCQmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  A series LCR circuit is connected to an AC source. When L alone is removed, current and applied voltage differ in phase by π/3. When C alone is removed, the phase difference is also π/3. What is the power factor of the full LCR circuit?

  Options

  • Option A

    0.5

  • Option B

    1.0

  • Option C

    -10

  • Option D

    Zero

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• MCQeasyAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  If I=$I_A$ sinωt + $I_B$ cosωt, the rms value of current is:

  Options

  • Option A

    $I_A+I_B$

  • Option B

    √($I_A²+I_B²)$

  • Option C

    √[($I_A²+I_B²)/2]$

  • Option D

    (1/2)√($I_A²+I_B²)$

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• MCQeasyAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  An alternating current is represented by i = I₀(sinωt + cosωt). What is the RMS value of this current over a complete cycle?

  Options

  • Option A

    I₀/√2

  • Option B

    I₀

  • Option C

    √2 I₀

  • Option D

    2I₀

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• NumericmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  A 20 Ω resistor carries the current i = 2 + 3√2 sinωt A. Calculate the average power dissipated in the resistor in watt.

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• Multi-correctmediumAC CircuitsAverage Value, RMS Value and Peak Value of Alternating Current

  A periodic current is described by i = I₀(1 + sinωt). Which of the following statements are correct when the current is observed over one complete cycle?

  Select all that apply

  • Option A

    The average current is I₀

  • Option B

    The RMS current is I₀√(3/2)

  • Option C

    The current never becomes negative

  • Option D

    The RMS current is equal to the average current

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