At t=0, A has r⃗_A=0, v⃗_A=4î and a⃗_A=2ĵ. B has r⃗_B=12î+16ĵ, v⃗_B=-2î and a⃗_B=-2ĵ. The relative position r⃗_BA is:
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Question

At t=0, A has r⃗_A=0, v⃗_A=4î and a⃗_A=2ĵ. B has r⃗_B=12î+16ĵ, v⃗_B=−2î and a⃗_B=−2ĵ. The relative position r⃗_BA is:

G1 Physics · Accepted Answer

r⃗₀=12î+16ĵ, v⃗_rel=−6î and a⃗_rel=−4ĵ. Therefore r⃗=r⃗₀+v⃗_relt+(1/2)a⃗_relt²=(12−6t)î+(16−2t²)ĵ.