A coin is at the bottom of a hemispherical container filled with a liquid of re $fractive$ index μ. From the geometry shown in the original figure, the limiting ray reaches the rim with incidence angle 45°. Find the least μ for which the coin is visible to the observer E.
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Question

A coin is at the bottom of a hemispherical container filled with a liquid of re $fractive$ index μ. From the geometry shown in the original figure, the limiting ray reaches the rim with incidence angle 45°. Find the least μ for which the coin is visible to the observer E.

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G1 Physics · Accepted Answer

For the limiting condition, critical angle θ_c=45°. Since sinθ_c=1/μ, μ=1/sin45°=√2.

A coin is at the bottom of a hemispherical container filled with a liquid of re \fractive \fractive \fractive index μ. From the geometry shown in the original figure, the limiting ray reaches the rim with incidence angle 45°. Find the least μ for which the coin is visible to the observer E.