A particle moves on a circle of radius 5 m. At an instant its speed is 10 m/s and dv/dt = 2 m/s². If the magnitude of acceleration is 2√N m/s², find N.
Physics · Circular Motion · kinematics of circular motion
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Question

A particle moves on a circle of radius 5 m. At an instant its speed is 10 m/s and dv/dt = 2 m/s². If the magnitude of acceleration is 2√N m/s², find N.

G1 Physics · Accepted Answer

Tangential acceleration aₜ=dv/dt=2 m/s². Radial acceleration a_c=v²/R=100/5=20 m/s². Thus a=√(20²+2²)=√404=2√101 m/s². Hence N=101.