The speed of a particle moving on a circle varies with arc length s as v² = v₀² + 2ks. Its tangential acceleration is:
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The speed of a particle moving on a circle varies with arc length s as v² = v₀² + 2ks. Its tangential acceleration is:

G1 Physics · Accepted Answer

aₜ=dv/dt=(dv/ds)(ds/dt)=v(dv/ds). Differentiating v²=v₀²+2ks with respect to s gives 2v(dv/ds)=2k, so v(dv/ds)=k. Therefore aₜ=k.