A particle moves on a circle with angular speed ω = ω₀eᵏᵗ, where k is a positive constant. The ratio aₜ/ $a_c$ is:
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Question

A particle moves on a circle with angular speed ω = ω₀eᵏᵗ, where k is a positive constant. The ratio aₜ/a_c is:

G1 Physics · Accepted Answer

α=dω/dt=kω. Therefore aₜ=Rα=Rkω and a_c=Rω². Hence aₜ/a_c = k/ω.