For the particle moving on a circle of radius 2 m with v² = 4 + 8s, the magnitude of net acceleration at s = 1 m is:
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For the particle moving on a circle of radius 2 m with v² = 4 + 8s, the magnitude of net acceleration at s = 1 m is:

G1 Physics · Accepted Answer

At s=1 m, v²=4+8=12. Therefore radial acceleration a_c=v²/R=12/2=6 m/s². From aₜ=½d(v²)/ds=4 m/s². Hence a=√(6²+4²)=√52=2√13 m/s².