A particle moves in a circle such that ω² = ω₀² + 4θ. Its angular acceleration is:
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Question

A particle moves in a circle such that ω² = ω₀² + 4θ. Its angular acceleration is:

G1 Physics · Accepted Answer

α=ω(dω/dθ)=½d(ω²)/dθ. Since d(ω²)/dθ=4, α=2 rad/s².