A slanted object AB is placed on one side of a convex lens as shown in the original figure. The image is formed on the opposite side. The angle made by the image with the principal axis is:

Question

G1 Physics · Accepted Answer

Using the dimensions shown in the original figure, point A is 30 cm from a convex lens of focal length 20 cm. For point A: 1/f = 1/v - 1/u, with f = +20 cm and u = -30 cm. Thus 1/20 = 1/v + 1/30 ⇒ 1/v = 1/60 ⇒ v = 60 cm. The transverse magnification magnitude near A is |m| = v/|u| = 60/30 = 2. The vertical separation of B from A is 2 cm, so the image vertical separation has magnitude |Δy'| = 2×2 = 4 cm, and it is inverted. For a small longitudinal object displacement, longitudinal magnification…