JEE Mains 2025 2 April Morning Shift physics questions with solutions

Showing 1–10 of 25 questions

• MCQmediumGeometrical opticsrefraction due to curved surface

  A spherical surface separates two media of refractive indices 1 and 1.5 as shown in the original figure. The object is 0.2 m to the left of the surface and the centre of curvature is 0.4 m to the right of the surface. The image is formed at:

  

  Options

  • Option A

    0.24 m right of the spherical surface

  • Option B

    0.4 m left of the spherical surface

  • Option C

    0.4 m right of the spherical surface

  • Option D

    0.24 m left of the spherical surface

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• IntegermediumProperties of solid and fluidpropertes of solid stress ,strain and modulus of elasticity

  A steel wire has Young's modulus 2.0×10¹¹ N m⁻². Its Poisson ratio is 0.2 and the magnitude of transverse strain is 10⁻³. The elastic potential-energy density is ______ ×10⁵ in SI units. Find the numerical value in the blank.

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• MCQmediumRotational Motiontorque and rotational equilibrium

  A square lamina OABC of side 10 cm is pivoted at O. Forces act on the lamina as shown in the original figure. If the lamina remains stationary, the magnitude of F is:

  

  Options

  • Option A

    10√2 N

  • Option B

    20 N

  • Option C

    10 N

  • Option D

    0

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• MCQmediumPhotoelectric effect and dual nature of matterquestion based on photoelectric effect

  A monochromatic light of wavelength λ is incident on a metallic plate of work function φ. An electron is emitted normally from point A with maximum kinetic energy and enters a uniform magnetic field B perpendicular to its initial velocity. It follows a circular path and hits the plate again at B. The distance AB is:

  Options

  • Option A

    √[2m(hc/λ - φ)]/(eB)

  • Option B

    √[m(hc/λ - φ)]/(eB)

  • Option C

    √[8m(hc/λ - φ)]/(eB)

  • Option D

    2√[m(hc/λ - φ)]/(eB)

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• MCQmediumSimple Harmonic Motionphysical pendulam and torsional pendulam ,combination of shm

  A particle is subjected to two simple harmonic motions: x₁ = √7 sin(5t) cm and x₂ = 2√7 sin(5t + π/3) cm. The maximum acceleration is x×10⁻² m s⁻². The value of x is:

  Options

  • Option A

    5√7

  • Option B

    175

  • Option C

    25√7

  • Option D

    125

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• MCQmediumRotational Motionrotational constrain motion

  A cord of negligible mass is wound around the rim of a wheel supported by spokes of negligible mass. The wheel has mass 10 kg and radius 10 cm and rotates freely without friction. Initially it is at rest. A steady pull of 20 N is applied to the cord. The angular velocity after the cord is unwound by 1 m is:

  

  Options

  • Option A

    20 rad/s

  • Option B

    10 rad/s

  • Option C

    30 rad/s

  • Option D

    0 rad/s

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• MCQeasyCurrent electricitycombination of cells and maximum power theorem

  A mobile-phone battery is rated 4.2 V, 5800 mAh. The energy stored when fully charged is:

  Options

  • Option A

    48.7 kJ

  • Option B

    43.8 kJ

  • Option C

    87.7 kJ

  • Option D

    24.4 kJ

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• MCQmediumsemiconductorapplication of diode and zener breakdown

  A Zener diode of Zener voltage 5 V is used to regulate an unregulated dc input of 25 V. A 400 Ω resistor is connected in series, and the Zener current is four times the load current. The load current I(L) and load resistance R(L) are:

  Options

  • Option A

    I(L)=10 A; R(L)=0.5 Ω

  • Option B

    I(L)=10 mA; R(L)=500 Ω

  • Option C

    I(L)=20 mA; R(L)=250 Ω

  • Option D

    I(L)=0.02 mA; R(L)=250 Ω

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• NumericeasyKinematics Part-1 (one dimension)Distance,Displacement ,Avg speed and Avg velocity

  A person travelling along a straight line moves with uniform velocity v₁ for a distance x and with uniform velocity v₂ for the next 3x/2 distance. The average velocity for the complete motion is 50/7 m/s. If v₁ = 5 m/s, find v₂ in m/s.

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• MCQeasyWave Opticsinterferece of light and huygen principle

  A light wave has plane wavefronts described by x + y + z = constant. The angle made by the direction of wave propagation with the x-axis is:

  Options

  • Option A

    cos⁻¹(1/√3)

  • Option B

    cos⁻¹(√(2/3))

  • Option C

    cos⁻¹(1/3)

  • Option D

    cos⁻¹(2/3)

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