A capacitor of capacitance 2 μF has voltage V = 10 sin(2000t) V across it. If the maximum displacement current is N mA, find N.

Question

G1 Physics · Accepted Answer

For a capacitor, displacement current = C(dV/dt). Given, V = 10 sin(2000t). Therefore, dV/dt = 20000 cos(2000t) V/s. Hence, displacement current = (2×10⁻⁶)(20000) cos(2000t) = 4×10⁻² cos(2000t) A. Maximum displacement current: I(max) = 4×10⁻² A = 40 mA. Hence N = 40.