A capacitor of capacitance 5 μF has potential difference V = 100t² V. At t = 0.02 s, if the displacement current is N μA, find N.

Question

G1 Physics · Accepted Answer

For a capacitor, displacement current = C(dV/dt). Given, V = 100t². Therefore, dV/dt = 200t. At t = 0.02 s, dV/dt = 200(0.02) = 4 V/s. Hence, displacement current = (5×10⁻⁶)(4) = 20×10⁻⁶ A = 20 μA. Therefore N = 20.