Three masses are connected by two light strings and a fixed smooth pulley. A 4 kg mass hangs on the left side of the upper string. On the right side of the same string hangs another 4 kg mass, and a 6 kg mass is suspended below it by a second string. Let T₁ be the tension in the upper string and T₂ the tension in the lower string. Taking g = 10 m·s⁻², what is the ratio T₁/T₂?
Physics · Newtons law of motion and Friction · simple pulley problem
Three masses are connected by two light strings and a fixed smooth pulley. A 4 kg mass hangs on the left side of the upper string. On the right side of the same string hangs another 4 kg mass, and a 6 kg mass is suspended below it by a second string. Let T₁ be the tension in the upper string and T₂ the tension in the lower string. Taking g = 10 m·s⁻², what is the ratio T₁/T₂?

Options