In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers i $s _____mm.$
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Question

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers i s _____mm.

G1 Physics · Accepted Answer

Given, 50 VSD = 48 MSD. Therefore, 1 VSD = 48/50 MSD. For a direct vernier, least count = 1 MSD - 1 VSD. Hence, LC = 1 MSD - 48/50 MSD = 2/50 MSD. Since 1 MSD = 0.05 mm, LC = (2/50)(0.05) = 0.002 mm. Correct option: A.