A body of moment of inertia 2×10⁻³ kg·m² is suspended by a torsion wire of torsional constant 0.18 N·m/rad. If the square of its angular frequency is N s⁻², find N.

Question

G1 Physics · Accepted Answer

For a torsional oscillator, Iθ̈ = −Cθ. Hence, ω² = C/I. Substitute C = 0.18 N·m/rad, I = 2×10⁻³ kg·m². Therefore, ω² = 0.18/(2×10⁻³) = 90 s⁻². Hence, N = 90.