A galvanometer G of 2 Ω resistance is connected in the given circuit. The ratio of charge stored in C₁ and C₂ is:

Question

G1 Physics · Accepted Answer

Image In steady state, capacitors behave as open circuits. Equivalent resistance: Rₑq = 4 Ω + 2 Ω + 6 Ω = 12 Ω Current: I = 6/12 = 0.5 A Potential difference across C₁: V₁ = 0.5 × 6 = 3 V Potential difference across C₂: V₂ = 0.5 × (4 + 2) = 4 V Charge on C₁: q₁ = C₁V₁ = 4 μF × 3 V = 12 μC Charge on C₂: q₂ = C₂V₂ = 6 μF × 4 V = 24 μC Therefore, q₁/q₂ = 1/2