An elastic spring under tension of 3 N has a length a. Its length is b under tension 2 N. For its length (3a - 2b), the value of tension will b e ______ N.

Question

G1 Physics · Accepted Answer

Let natural length be ℓ₀ and spring constant be K. For length a: 3 = K(a - ℓ₀) For length b: 2 = K(b - ℓ₀) Required tension: T = K[(3a - 2b) - ℓ₀] = K[3(a - ℓ₀) - 2(b - ℓ₀)] = 3(3) - 2(2) = 9 - 4 = 5 N