A wooden block of mass 5kg rests on soft horizontal floor. When an iron cylinder of mass 25 kg is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 m s⁻². The action force of the system on the floor is equal to:
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Question

A wooden block of mass 5kg rests on soft horizontal floor. When an iron cylinder of mass 25 kg is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 m s⁻². The action force of the system on the floor is equal to:

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G1 Physics · Accepted Answer

Total mass: M = 5 + 25 = 30 kg Taking downward direction as positive: Mg - N = Ma 30 × 9.8 - N = 30 × 0.1 294 - N = 3 Therefore: N = 291 N By Newton's third law, the action force on the floor has the same magnitude.