A light string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (where m₂ > m₁). If the acceleration of the system is g/√2, then the ratio of the masses m₁/m₂ is :
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Question

A light string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (where m₂ > m₁). If the acceleration of the system is g/√2, then the ratio of the masses m₁/m₂ is :

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G1 Physics · Accepted Answer

For an Atwood machine: a = [(m₂ - m₁)/(m₁ + m₂)]g Given: a = g/√2 Therefore: 1/√2 = (m₂ - m₁)/(m₁ + m₂) Rearranging: m₁/m₂ = (√2 - 1)/(√2 + 1)

A light string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (where m₂ &gt; m₁). If the acceleration of the system is g/√2, then the ratio of the masses m₁/m₂ is :

A light string passing over a smooth light pulley connects two blocks of masses m₁ and m₂ (where m₂ > m₁). If the acceleration of the system is g/√2, then the ratio of the masses m₁/m₂ is :