A 1 kg mass is suspended from the ceiling by a rope of length 4m. A horizontal force 'F' is applied at the mid point of the rope so that the rope makes an angle of 45° with respect to the vertical axis as shown in figure. The magnitude of F is :

Question

G1 Physics · Accepted Answer

Image At the midpoint: T₁ sin45° = F For the lower vertical segment: T₂ = mg = 1 × 10 = 10 N Vertical equilibrium at the midpoint gives: T₁ cos45° = T₂ Therefore: tan45° = F/T₂ 1 = F/10 Hence: F = 10 N