A screw gauge has pitch p and 80 circular-scale divisions. Its least count is 0.004 mm. If the screw advances through 3.2 mm in a certain number of complete rotations, that number is:
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Question

A screw gauge has pitch p and 80 circular-scale divisions. Its least count is 0.004 mm. If the screw advances through 3.2 mm in a certain number of complete rotations, that number is:

G1 Physics · Accepted Answer

LC = p/80 = 0.004 mm, so p = 0.32 mm per rotation. Number of rotations = 3.2/0.32 = 10.