A vernier calipers has N VSD equal to (N - 2) MSD. If 1 MSD = 1 mm and its least count is the same as that of a screw gauge of pitch 0.5 mm having 100 circular divisions, N equals:
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A vernier calipers has N VSD equal to (N − 2) MSD. If 1 MSD = 1 mm and its least count is the same as that of a screw gauge of pitch 0.5 mm having 100 circular divisions, N equals:

G1 Physics · Accepted Answer

Screw-gauge LC = 0.5/100 = 0.005 mm. Vernier LC = (2/N)(1 mm). Equating gives 2/N = 0.005, hence N = 400.