A screw gauge has pitch 0.4 mm and 80 circular divisions. For a wire, PSR = 1.2 mm and CSR = 56. The zero error is -0.015 mm. Which statements are correct?
Select all that apply

Question

A screw gauge has pitch 0.4 mm and 80 circular divisions. For a wire, PSR = 1.2 mm and CSR = 56. The zero error is −0.015 mm. Which statements are correct?

G1 Physics · Accepted Answer

LC = 0.4/80 = 0.005 mm. Observed = 1.2 + 56(0.005) = 1.48 mm. Negative zero error gives positive correction, so corrected diameter = 1.495 mm.