Given below are two statements : Statement I : If the Brewster’s angle for the light propagating from air to glass is $\theta_{B}$ , then Brewster’s angle for the light propagating from glass to air is π/2 - $\theta_{B}$ . Statement II : The Brewster’s angle for the light propagating from glass to air is tan⁻¹(μ(glass)) where μ(glass) is the refractive index of glass. In the light of the above statements, choose the correct answer from the options given below :
Options

Question

Given below are two statements : Statement I : If the Brewster’s angle for the light propagating from air to glass is $\theta_{B}$ , then Brewster’s angle for the light propagating from glass to air is π/2 - $\theta_{B}$ . Statement II : The Brewster’s angle for the light propagating from glass to air is tan⁻¹(μ(glass)) where μ(glass) is the refractive index of glass. In the light of the above statements, choose the correct answer from the options given below :

Options

G1 Physics · Accepted Answer

For air to glass, tan i₁ = μ(glass)/μ(air). For glass to air, tan i₂ = μ(air)/μ(glass) = cot i₁. Therefore i₂ = π/2 - i₁, so Statement I is true. Statement II is false because for glass to air, tan i₂ = μ(air)/μ(glass). If air is taken as μ(air) ≈ 1, then tan i₂ = 1/μ(glass), not μ(glass).