Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, γ₁/γ₂ is
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Question

Let γ₁ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ₂ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio, γ₁/γ₂ is

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G1 Physics · Accepted Answer

For a monoatomic gas, γ₁ = 5/3. For a diatomic gas treated as a rigid rotator, γ₂ = 7/5. Therefore γ₁/γ₂ = (5/3)/(7/5) = 25/21.