A particle is thrown with a speed v from a point O at an angle θ with the horizontal plane such that it passes through the point P at a height of 1 m and horizontal distance of 5 m from O, as shown in the figure. If acceleration due to gravity is g m s⁻², then the correct statement(s) is/are:

Question

G1 Physics · Accepted Answer

Projectile equation at x = 5 m, y = 1 m is 1 = 5tanθ − [25g/(2v²cos²θ)]. For θ = 45°, this gives v² = 25g/4, hence v = 5√g/2, so A is correct. At θ = 45°, x at the highest point is v²sin2θ/(2g) = 25/8 m < 5 m, so the maximum height is reached before P; B is correct. The remaining statements are false.