Speed of an electron in Bohr’s 7th orbit for Hydrogen atom is 3.6 × 10⁶ m s⁻¹. The corresponding speed of the electron in 3rd orbit, in m s⁻¹, is:
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Speed of an electron in Bohr’s 7th orbit for Hydrogen atom is 3.6 × 10⁶ m s⁻¹. The corresponding speed of the electron in 3rd orbit, in m s⁻¹, is:

G1 Physics · Accepted Answer

For hydrogen, vₙ ∝ 1/n. Therefore v₃/v₇ = 7/3, so v₃ = (7/3)(3.6×10⁶) = 8.4×10⁶ m s⁻¹.