A capacitor of capacitance 900 μF is charged by a 100 V battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor with corresponding plates joined. The loss of energy in this process is measured as x × 10⁻² J. The value of x is ____.
Physics · Circular Motion
JEE Mains 30 January 2023 Shift 1 Morning Shift

Question

A capacitor of capacitance 900 μF is charged by a 100 V battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor with corresponding plates joined. The loss of energy in this process is measured as x × 10⁻² J. The value of x is ____.

Physics · Circular Motion

JEE Mains 30 January 2023 Shift 1 Morning Shift

G1 Physics · Accepted Answer

Initial energy Uᵢ = (1/2)CV² = (1/2)(900×10⁻⁶)(100)² = 4.5 J. Final common voltage is 50 V. Total final energy in two capacitors is 2×(1/2)C(50)² = 2.25 J. Energy loss = 2.25 J = 225×10⁻² J. Hence x = 225.