Expression for an electric field is E = 4000x² î V m⁻¹. The electric flux through the cube of side 20 cm when placed as shown in the figure is ______ V cm. Image
Physics · Circular Motion
JEE Mains 31 January 2023 Shift 1 Morning Shift

Question

Expression for an electric field is E = 4000x² î V m⁻¹. The electric flux through the cube of side 20 cm when placed as shown in the figure is ______ V cm. Image

G1 Physics · Accepted Answer

Only the two faces normal to x contribute. At x=0, E=0; at x=0.20 m, E=4000(0.20)²=160 V m⁻¹. Face area = (0.20)² = 0.04 m². Flux = 160×0.04 = 6.4 V m = 640 V cm.