A series LCR circuit consists of R = 80 Ω, X(L) = 100 Ω and X(C) = 40 Ω. The input voltage is 2500 cos(100πt) V. The amplitude of current in the circuit is ______ A.
Physics · Circular Motion
JEE Mains 31 January 2023 Shift 2 Evening Shift

Question

A series LCR circuit consists of R = 80 Ω, X(L) = 100 Ω and X(C) = 40 Ω. The input voltage is 2500 cos(100πt) V. The amplitude of current in the circuit is ______ A.

G1 Physics · Accepted Answer

Impedance Z = √[R² + (X(L)−X(C))²] = √(80²+60²) = 100 Ω. Since 2500 V is the voltage amplitude, current amplitude = 2500/100 = 25 A.