A solid cylinder is released from rest from the top of an inclined plane of inclination 30° and length 60 cm. If it rolls without slipping, its speed at the bottom i $s ______$ m s⁻¹. [g = 10 m s⁻²]

Question

G1 Physics · Accepted Answer

Vertical drop h = 0.60 sin30° = 0.30 m. For a solid cylinder, I = (1/2)MR². Energy conservation gives Mgh = (1/2)Mv² + (1/2)I(v²/R²) = ( 3 4 \frac{3}{4} 4 3 ​ )Mv². Thus v² = 4gh/3 = 4, so v=2 m s⁻¹.

A solid cylinder is released from rest from the top of an inclined plane of inclination 30° and length 60 cm. If it rolls without slipping, its speed at the bottom i s ______ m s⁻¹. [g = 10 m s⁻²]