In this figure the resistance of the galvanometer coil G is 2 Ω and the emf of the cell is 4 V. The ratio of potential differences across C₁ and C₂ is:

Question

G1 Physics · Accepted Answer

In steady DC condition, no current flows through the capacitor branches. Therefore the node potentials are fixed only by the resistive network shown in the figure. Using the resistor voltage-divider relations for the two capacitor terminals and then using V = Q/C, the ratio of the potential differences across C₁ and C₂ is obtained as V(C₁)/V(C₂) = 4/5 Hence option C follows.