Proton (P) and electron (e) will have same de-Broglie wavelength when the ratio of their momentum is (assume, mp = 1849 me):
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Question

Proton (P) and electron (e) will have same de-Broglie wavelength when the ratio of their momentum is (assume, mp = 1849 me):

G1 Physics · Accepted Answer

de Broglie wavelength is λ = h/p For proton and electron to have the same wavelength, h/p(p) = h/p(e) Therefore, p(p) = p(e) So the momentum ratio is p(p):p(e) = 1:1 Hence option D follows.