For a nucleus with mass number A and atomic number Z: A. The surface energy per nucleon is b(s) = −a₁A²ᐟ³. B. The Coulomb contribution to the binding energy is b(c) = −a₂Z(Z − 1)/A⁴ᐟ³. C. The volume energy is b(v) = a₃A. D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. Here a₁, a₂ and a₃ are constants. Choose the most appropriate answer from the options given below:
Physics · Circular Motion
For a nucleus with mass number A and atomic number Z: A. The surface energy per nucleon is b(s) = -a₁A²ᐟ³. B. The Coulomb contribution to the binding energy is b(c) = -a₂Z(Z - 1)/A⁴ᐟ³. C. The volume energy is b(v) = a₃A. D. Decrease in the binding energy is proportional to surface area. E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. Here a₁, a₂ and a₃ are constants. Choose the most appropriate answer from the options given below:
Options