The magnetic intensity at the centre of a long current-carrying solenoid is 1.6 × 10³ A m⁻¹. If the number of turns is 8 per cm, the current is ______ A.
Physics · Circular Motion
JEE Mains 8 April 2023 Shift 1 Morning Shift

Question

The magnetic intensity at the centre of a long current-carrying solenoid is 1.6 × 10³ A m⁻¹. If the number of turns is 8 per cm, the current is ______ A.

G1 Physics · Accepted Answer

For a long solenoid, magnetic field intensity is H = nI Turns per unit length: n = 8 turns/cm = 800 turns/m Given: H = 1.6×10³ A m⁻¹ Therefore, I = H/n = 1.6×10³ / 800 = 2 A Final value: 2