An emf of 0.08 V is induced in a metal rod of length 10 cm held normal to a uniform magnetic field of 0.4 T, when moves with a velocity of:
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Question

An emf of 0.08 V is induced in a metal rod of length 10 cm held normal to a uniform magnetic field of 0.4 T, when moves with a velocity of:

G1 Physics · Accepted Answer

Motional emf is ε = Blv when the rod moves perpendicular to both its length and the magnetic field. Given: ε = 0.08 V B = 0.4 T l = 10 cm = 0.10 m Therefore, v = ε/(Bl) = 0.08/(0.4×0.10) = 0.08/0.04 = 2 m s⁻¹ Hence option A follows.