The range of a projectile projected at an angle of 15° with the horizontal is 50 m. If the projectile is projected with the same speed at an angle of 45° with the horizontal, its range will be:
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Question

The range of a projectile projected at an angle of 15° with the horizontal is 50 m. If the projectile is projected with the same speed at an angle of 45° with the horizontal, its range will be:

G1 Physics · Accepted Answer

Projectile range is R = u²sin2θ/g For θ = 15°: 50 = u²sin30°/g = u²/(2g) Therefore, u²/g = 100 For θ = 45°: R' = u²sin90°/g = u²/g = 100 m Hence option C follows.