The angular momentum of an electron in the first Bohr orbit is L. If it revolves in the second orbit, the change in angular momentum is:
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Question

The angular momentum of an electron in the first Bohr orbit is L. If it revolves in the second orbit, the change in angular momentum is:

G1 Physics · Accepted Answer

Bohr quantization gives Lₙ = nh/(2π) For n = 1: L₁ = h/(2π) = L For n = 2: L₂ = 2h/(2π) = 2L Therefore, ΔL = L₂ − L₁ = 2L − L = L Hence option C follows.