A wire of density 8 × 10³ kg m⁻³ is stretched between clamps 0.5 m apart. Its extension is 3.2 × 10⁻⁴ m. If Y = 8 × 10¹⁰ N m⁻², find its fundamental frequency in Hz.

Question

G1 Physics · Accepted Answer

Tension T = YA(ΔL/L). Linear mass density μ = ρA. Fundamental frequency f = (1/2L)√(T/μ) = (1/2L)√[YΔL/(ρL)]. Substitute L=0.5 m, Y=8×10¹⁰, ΔL=3.2×10⁻⁴, ρ=8×10³: f = 80 Hz. Final value: 80