In alpha decay, ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Q. Given masses 238.05060 u, 234.04360 u and 4.00260 u, and 1 u = 931.5 MeV/c². The energy released, rounded to the numerical value accepted by the source, i s ______ MeV.
Physics · Nuclear physics · radioactivity and law of decay
In alpha decay, ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He + Q. Given masses 238.05060 u, 234.04360 u and 4.00260 u, and 1 u = 931.5 MeV/c². The energy released, rounded to the numerical value accepted by the source, is ______ MeV.